DGELSS Example

To solve the linear least squares problem

$$\min_{{x}}^{}$$$$\left\Vert\vphantom{ b - A x }\right.$$b - Ax$$\left.\vphantom{ b - A x }\right\Vert _{{2}}^{}$$

for the solution, x, of minimum norm, where

A = $$\left(\vphantom{ \begin{array}{rrrrr} -0.09 & 0.14 & -0.46 & 0.... ...13 & 0.14 & 1.74 \\ -1.59 & -0.72 & 1.06 & 1.24 & 0.34 \end{array} }\right.$$$$\begin{array}{rrrrr} -0.09 & 0.14 & -0.46 & 0.68 & 1.29 \\ -1... ....55 & -1.13 & 0.14 & 1.74 \\ -1.59 & -0.72 & 1.06 & 1.24 & 0.34 \end{array}$$$$\left.\vphantom{ \begin{array}{rrrrr} -0.09 & 0.14 & -0.46 & 0.... ...13 & 0.14 & 1.74 \\ -1.59 & -0.72 & 1.06 & 1.24 & 0.34 \end{array} }\right)$$  and  b = $$\left(\vphantom{ \begin{array}{r} 7.4 \\ 4.2 \\ -8.3 \\ 1.8 \\ 8.6 \\ 2.1 \end{array} }\right.$$$$\begin{array}{r} 7.4 \\ 4.2 \\ -8.3 \\ 1.8 \\ 8.6 \\ 2.1 \end{array}$$$$\left.\vphantom{ \begin{array}{r} 7.4 \\ 4.2 \\ -8.3 \\ 1.8 \\ 8.6 \\ 2.1 \end{array} }\right)$$.

A tolerance of 0.01 is used to determine the effective rank of A.

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